the smallest whole number ratio of elects in a compound

Answer:

24.31 g/mol.

Explanation:

moles =mass/molar mass

n=w/m

Answer:

B) Mass- I searched it up

Answer: Solubility increases so more solute dissolves

Explanation:

The solubility is a measure of the concentration of the dissolved gas particles in the liquid and is a function of the gas pressure. As you increase the pressure of a gas, the collision frequency increases and thus the solubility goes up, as you decrease the pressure, the solubility goes down.

Answer:

3 moles H2 x (molecules / 1 mol H2)

Explanation:

3 moles H2 x (molecules / 1 mol H2)

The volume of the nitrogen oxide gas is 35.2 L

Stoichiometry is the quantitative study of reactants and products in a chemical reaction. It is used to determine the amount of reactants needed to produce a certain amount of product, or to determine the amount of product that will be produced from a given amount of reactant.

To apply stoichiometry;

We know that;

Number of moles of Cu = 150/ 63.5g/mol = 2.36 moles

If 3 moles of Cu produced 2 moles of NO

2.36 moles of Cu will produce 2.36 * 2/3

= 1.57 moles

If 1 moles of NO occupies 22.4 L

1.57 moles of NO will occupy 1.57 * 22.4/1

= 35.2 L

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No, 28 moles of solid carbon would not be enough to produce 15 moles of [tex]C_2H_6[/tex] (Ethane).

This is because the reaction requires more than 1 mole of carbon to produce 1 mole of [tex]C_2H_6[/tex]. The mole ratio of [tex]C_2H_6[/tex]:C is 2:1, so 28 moles of carbon would only be enough to produce 14 moles of [tex]C_2H_6[/tex].A chemical compound having the molecular formula  [tex]C_2H_6[/tex], ethane is an organic substance. Ethane is an odourless, colourless gas at ordinary pressure and temperature. Ethane is separated from natural gas on an industrial scale, and it is produced as a by-product of the petrochemical process used to refine crude oil. Its primary usage is as a feedstock for the creation of ethylene.The ethane moiety is known as an ethyl group, and it can be used to create related compounds by swapping out a hydrogen atom for another functional group.

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Answer:

many milliliters of 1.50 M HCl(aq) are required to react with 5.05 g Zn(s)?

volume: 16 mL

First, we need to calculate the number of moles of Zn:

m(Zn) = 5.05 g

M(Zn) = 65.38 g/mol (molar mass of Zn)

n(Zn) = m(Zn) / M(Zn) = 5.05 g / 65.38 g/mol = 0.0773 mol

According to the balanced chemical equation, 1 mole of Zn reacts with 2 moles of HCl. Therefore, the number of moles of HCl needed is:

n(HCl) = 2 × n(Zn) = 2 × 0.0773 mol = 0.1546 mol

Now we can use the molarity of the HCl solution to calculate the volume needed:

M(HCl) = 1.50 mol/L

n(HCl) = V(HCl) × M(HCl)

V(HCl) = n(HCl) / M(HCl) = 0.1546 mol / 1.50 mol/L = 0.103 L = 103 mL

Therefore, we need 103 mL of 1.50 M HCl(aq) to react with 5.05 g Zn(s).

Answer:

Continuous Spectrum, a spectrum that contains all wavelengths of light within a specific range, with no gaps or lines. It is produced by a hot, dense object such as a star or a light bulb.

Emission Spectrum, a spectrum that contains bright lines or bands of specific wavelengths, with dark spaces in between. It is produced when light is emitted from a hot gas or plasma, and the specific wavelengths of the lines or bands depend on the elements present in the gas.

Absorption Spectrum, a spectrum that contains dark lines or bands of specific wavelengths, with bright spaces in between. It is produced when a continuous spectrum passes through a cool gas, and the specific wavelengths of the lines or bands depend on the elements present in the gas.

When a protonated epoxide is attacked by water, the nucleophile attacks from the "top" or "front" of the epoxide ring in an "S_N2" substitution nucleophilic bimolecular process.

A protonated epoxide is a molecule that contains an epoxide ring (a three-membered ring consisting of two carbon atoms and one oxygen atom) that has been protonated, or had a hydrogen ion (H+) added to it.

The protonation of an epoxide ring can occur in the presence of an acidic medium, such as a strong acid like sulfuric acid (H2SO4) or hydrochloric acid (HCl).

In acidic conditions, the lone pair of electrons on the oxygen atom of the epoxide ring can interact with the positively charged hydrogen ion, resulting in the formation of a protonated epoxide.

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Answer:

D

Explanation:

The mole fraction of HCl in the given solution is 0.051.

To calculate the mole fraction of HCl in the given solution, we need to first find the mass of HCl and water present in the solution.

Let's assume we have 100 g of the solution, so 9.8 g of it is HCl, and 90.2 g is water.

Next, we need to find the moles of HCl present in the solution.

To do this, we divide the mass of HCl by its molar mass.

The molar mass of HCl is 36.46 g/mol (1.01 g/mol for hydrogen + 35.45 g/mol for chlorine).

moles of HCl = 9.8 g / 36.46 g/mol = 0.269 mol

The moles of water can be calculated using its molar mass which is 18.015 g/mol.

moles of water = 90.2 g / 18.015 g/mol = 5.005 mol

The total number of moles in the solution is the sum of the moles of HCl and water.

total moles = 0.269 mol + 5.005 mol = 5.274 mol

The mole fraction of HCl can now be calculated by dividing the moles of HCl by the total number of moles.

mole fraction of HCl = 0.269 mol / 5.274 mol = 0.051

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The substance is lithium (Li).

Isotopes are atoms of the same element with variable numbers of neutrons but the same number of protons in their nucleus.

Hence, although having different atomic masses, they have the same atomic number.

The physical characteristics of an element's isotopes can differ from their chemical characteristics because of their varied atomic masses.

Isotopes include, for instance:

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Answer:

The nuclide formed by the β decay of 26Al is 26Mg.


Mark my answer as brainliest! this was a difficult one

Explanation:

Answer:

To solve this problem, we can use the Boyle's Law equation, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's Law: P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.

Using the given values:

P1 = 30.0 atm

V1 = 2 L

P2 = 10.0 atm

Substituting these values into the Boyle's Law equation, we get:

30.0 atm x 2 L = 10.0 atm x V2

Simplifying and solving for V2, we get:

V2 = (30.0 atm x 2 L) / 10.0 atm

V2 = 6 L

Therefore, the new volume of the gas will be 6 L if the pressure is reduced to 10.0 atm, assuming the temperature remains constant.

I Hope This Helps!

Answer:

4 millllllermeeters jb

The mass(in grams) of iron, Fe produced from the 92.5g of iron (ii) oxide, FeO is 71.9 grams

The mass of Fe produced from the 92.5g of iron (ii) oxide, FeO can be obtained as follow:

2FeO → 2Fe + O₂

From the balanced equation above,

143.7 g of FeO reacted to produce 111.7 g of Fe

Therefore,

92.5 g of Fe will react to produce = (92.5 × 111.7) / 143.7 = 71.9 g of Fe

Thus, the mass of Fe produced from the reaction is 71.9 grams

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Complete question:

How many grams of Fe are produced from 92.5 g of FeO given the following reaction 2FeO → 2Fe + O₂

Answer:

D

Explanation:

because replusive force is much more

The volume of the gas will be 560 mL when the pressure is reduced to 125.0 kPa, assuming the temperature remains constant.

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Substituting the given values, we get:

P₁ = 350.0 kPa (initial pressure)

V₁ = 200 mL (initial volume)

P₂ = 125.0 kPa (final pressure)

V₂ = ?

Solving for V₂, we get:

V₂ = ( P₁ × V₁ ) / P₂

V₂ = (350.0 kPa × 200 mL) / 125.0 kPa

V₂ = 560 mL

Therefore, the final volume of the gas is  560 mL.

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Absolute magnitude, on the other hand, is a measure of how bright a star would appear if it were located at a standard distance of 10 parsecs (32.6 light-years) away from Earth.

What is Magnitude?

Magnitude is a measure of the brightness of a celestial object, such as a star, planet, or galaxy. It is based on the amount of light that is emitted by the object and is typically expressed using a numerical scale. The lower the magnitude value, the brighter the object appears.

Apparent magnitude is a measure of how bright an object appears to an observer on Earth, while absolute magnitude is a measure of how bright an object would appear if it were located at a standard distance of 10 parsecs (32.6 light-years) away from Earth.

Apparent magnitude is a measure of how bright a star appears to an observer on Earth. It is determined by the amount of light that reaches Earth from the star, as well as the distance between the star and Earth. As humans travel away from our solar system and to other solar systems, the distance between them and the stars will change, which will affect how bright the stars appear to the travelers. As they move closer to a star, its apparent magnitude will increase, and as they move away, its apparent magnitude will decrease.

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Answer:

The density of an object is constant.

Density is a derived unit of measure.

The density of an object determines whether it will sink or float.

Answer:

d

Explanation:

Nitrogen is the limiting reactant.

42 g N2x (1mole N2/28 g N2) X (2 moles NH3/ 1mole N2) X (17 grams NH3/1mole NH3) = 51 g

13 g H2 x (1 mole H2/2 g H2) X (2 moles NH3/3moles H2) X (17 g NH3/1mole NH3) =73.66g

since 51 is smaller than 73.66 and it started with N2 that is why N2 is the limiting reactant)

Answer:

21% percent

Explanation:

Air has small amounts of other gases, such as carbon dioxide,neon, and hydrogen. Oxygen shares some parts of air basically. The highest percentage of oxygen we can breathe is approximately 60℅

Answer: The amount of heat absorbed for the reaction of 25 mL of 1.0 M H₂SO4 and 50 mL of 1.0 M NaOH, resulting in a temperature increase from 25°C to 33.9°C, is 10.14 kJ.

Explanation:

Under the same conditions, the root mean square speed of F2(g) molecules is approximately 400 m/s.

The root mean square (rms) speed of a gas molecule can be calculated using the following equation:

rms speed = sqrt((3RT)/M)

where R is the gas constant, T is the temperature in Kelvin, and M is the molar mass of the gas molecule.

To use this equation to find the rms speed of F2(g) molecules, we need to know the temperature and molar mass of F2(g).

Let's assume that F2(g) is at the same temperature as He(g), and that the molar mass of F2(g) is 38.0 g/mol (the molar mass of F2).

Using the given average kinetic energy of He(g) and the molar mass of He(g) (4.00 g/mol), we can solve for the temperature:

(3/2)kT = average kinetic energy per mole

where k is the Boltzmann constant

(3/2)(1.38 x 10^-23 J/K)(T) = 7450 J/mol

T = 7450 J/mol / ((3/2)(1.38 x 10^-23 J/K)) = 346 K

Now we can use the rms speed equation to find the rms speed of F2(g):

rms speed = sqrt((3RT)/M) = sqrt((3 x 8.31 J/mol K x 346 K)/(38.0 g/mol))

rms speed = 400 m/s (rounded to three significant figures)

Therefore, under the same conditions, the root mean square speed of F2(g) molecules is approximately 400 m/s.

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40.5%

Explanation:

Ca×1 = 40

C×4 = 48

H×6 = 6

O×4 = 64

64÷158×100% = 40.5%

To solve for Δ2, we need to reverse the reaction and change the sign of Δ1:

2Al2O3(s)⟶4Al(s)+3O2(g)Δ2 = -Δ1

Therefore, Δ2 = -Δ1.

To solve for Δ3, we need to add the reactions for the formation of two moles of Al2O3 from aluminum and oxygen:

4Al(s)+3O2(g)⟶2Al2O3(s)Δ1

2Al2O3(s)⟶4Al(s)+3O2(g)Δ3

Adding these equations gives:

12Al(s)+9O2(g)⟶6Al2O3(s)Δ3

Therefore, Δ3 = 2Δ1.

To solve for Δ4, we need to divide the reaction for the formation of two moles of Al2O3 by two:

2Al(s)+3O2(g)⟶Al2O3(s)Δ1/2

Multiplying this equation by 16 gives:

32Al(s)+48O2(g)⟶16Al2O3(s)8Δ1/2

We can then cancel out the formation of 14 moles of Al2O3:

2Al(s)+32O2(g)⟶Al2O3(s)Δ4 = 8Δ1/2 - 7Δ1

Therefore, Δ4 = 8Δ1/2 - 7Δ1.