The major objective of a flyby spacecraft is to watch and record without getting snared by the planet's gravity, which is why flyby spacecraft should not be mistaken with orbiter spacecraft.
Flyby of the PlanetsAs a result of all the interplanetary navigation and course corrections completed during the mission, the spacecraft is positioned at the exact right spot and time to conduct its encounter observations. Data collection by a flyby spacecraft is not always possible.planets' orbits: A spaceship carrying out an orbiter mission must employ the same extremely precise interplanetary navigation and course correction techniques as those used for flyby missions. In order to enter planetary orbit, this technique positions the spacecraft exactly where it needs to be at the right time. Together with exact positioning and timing, controlled deceleration is also necessary for orbit insertion.For more information on planetary flyby and orbit kindly visit to
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a space traveler weighs 682 n on earth. what will the traveler weigh on another planet whose radius is 3 times that of earth and whose mass is 2 times that of earth?
The traveler's weight on another planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth is 21.647 N
The following is the solution to the given problem:
Mass and gravity are related to one another. Gravity is generated by the planet's mass, and the magnitude of the gravitational force is determined by the mass of the planet on which the object is situated, as well as the mass of the object.
Mass, distance, and gravity are all factors that influence the gravitational force. Mass is directly proportional to the gravitational force and inversely proportional to the square of the distance from the gravitational force's center.
Here is the formula: Force of gravity = G(M1M2)/d²where, G is the gravitational constant 6.67 x 10^{-11} N(m/kg)^2, M1 is the mass of the first body, M2 is the mass of the second body, d is the distance between the centers of two bodies.
On earth, the traveler weighs 682 N. On another planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth, we have to calculate the traveler's weight.
Mass of Earth is 5.972 × 10^24 kg2,
Radius of Earth is 6.371 x 10^63.
The mass of the planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth.
Mass of the planet = 2 x mass of Earth = 2 x 5.972 × 10^24 kg = 1.1944 × 10^25 kg4.
The radius of the planet whose radius is 3 times that of Earth,
Radius of the planet = 3 x radius of Earth = 3 x 6.371 x 10^6 m = 1.9113 × 10^7 m5.
The distance between the two planets.
Distance between two planets = radius of planet + radius of Earth
= 1.9113 × 10^7 m + 6.371 x 10^6 m
= 2.54813 x 10^7 m
= 2.54813 x 10^10 cm.
Putting all the values in the formula.
Force of gravity = G (M1 M2) / d²
Where, Mass of the traveler on the other planet is m.
Mass of the Earth is M1 = 5.972 × 10^24 kg.
Mass of the other planet is M2 = 2 x 5.972 × 10^24 kg = 1.1944 × 10^25 kg.
Radius of the Earth is r1 = 6.371 x 10^6 m.
Radius of the other planet is r2 = 3 x 6.371 x 10^6 m = 1.9113 × 10^7 m.
Distance between the two planets is d = 2.54813 x 10^10 cm.682
= G (M1 M2)/d²
G = 6.674 × 10^-11 N m² / kg²
Force of gravity on other planet = G(mM2)/r² where m is the mass of the traveler on the other planet
= 6.674 × 10^-11 × (m × 1.1944 × 10^25)/(1.9113 × 10^7)²
Weight on another planet = force of gravity on another planet × mass of the traveler on another planet
= (6.674 × 10^-11 × (m × 1.1944 × 10^25)/(1.9113 × 10^7)²) × m
= 21.647 N (approximately)
Therefore, the traveler's weight on another planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth is 21.647 N (approximately).
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in young's singe slit experiment, if the width of the slit decreases, what happends to the width of the diffracted peaks?
In Young's single slit experiment, if the width of the slit decreases, the width of the diffracted peaks increases.
Young's experiment involves a single slit that diffracts light and produces a pattern of bright and dark fringes on a screen. The width of the slit affects the diffraction of light through the slit and determines the width of the bright fringes on the screen.
The narrower the slit, the greater the diffraction of light, which causes the bright fringes to become wider.
This is because diffraction causes the light waves to spread out as they pass through the narrow slit, leading to interference and the formation of bright and dark fringes on the screen.
Therefore, if the width of the slit decreases, the width of the diffracted peaks increases.
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if the frequency of the incoming light is decreased, will the energy of the ejected electrons increase, decrease, or stay the same?
If the frequency of the incoming light is decreased, the energy of the ejected electrons will decrease.
The frequency of the incoming light will affect the energy of the ejected electrons. This is because the energy of the ejected electrons is proportional to the frequency of the incoming light.
The energy of the electrons can be determined using the equation:
E = h * f,
where E is the energy, h is Planck’s constant, and f is the frequency of the incoming light. This equation shows that the energy of the electrons is directly proportional to the frequency of the incoming light.
Therefore, if the frequency of the incoming light is decreased, the energy of the ejected electrons will also decrease.
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kim holds a 2.0 kg air rifle loosely and fires a bullet of mass 1.0 g. the muzzle velocity of the bullet is 150 m/s. calculate the recoil speed of the rifle.
The recoil speed of the rifle is 0.075 m/s in the opposite direction to the direction of the bullet.
To calculate the recoil speed of the rifle, we can use the conservation of momentum principle. According to this principle, the total momentum of the system (bullet + rifle) is conserved before and after the firing of the bullet.
Initially, the total momentum of the system is zero because the rifle and bullet are at rest. After firing the bullet, the total momentum of the system is given by:
m1v1 + m2v2 = 0
where m1 and v1 are the mass and velocity of the bullet, and m2 and v2 are the mass and recoil velocity of the rifle, respectively.
Substituting the given values, we get:
(0.001 kg)(150 m/s) + (2.0 kg)(v2) = 0
Solving for v2, we get:
v2 = -(0.001 kg)(150 m/s) / (2.0 kg)
v2 = -0.075 m/s
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a hard drive rotates at 7200 rpm. the disk has a diameter of 5.1 in 13 cm. what is the speed of a point 6.0 cm. from the center axle? what is the acceleration of this point on the disk.
The speed of a point 6.0 cm from the center axle is approximately 4.524 cm/s, and the acceleration of this point on the disk is approximately 3.408 cm/s².
The first step to solving this problem is to convert the rotational speed from revolutions per minute (rpm) to radians per second (rad/s):
ω = (7200 rpm) * (2π rad/rev) / (60 s/min) ≈ 753.98 rad/s
The speed of a point 6.0 cm from the center axle can be found using the formula:
v = r * ω
where r is the distance from the center axle to the point of interest. Substituting the given values, we get:
v = (6.0 cm) * 0.75398 rad/s ≈ 4.524 cm/s
To find the acceleration of this point on the disk, we can use the formula for centripetal acceleration:
a = r * ω²
where r is the distance from the center axle to the point of interest, and ω is the angular velocity in radians per second. Substituting the given values, we get:
a = (6.0 cm) * (0.75398 rad/s)² ≈ 3.408 cm/s²
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what must the tension in each cable be in the diagram in order to order to support the cargo in static equilibrium?
The tension in each cable must be equal to the mass of the cargo multiplied by the acceleration due to gravity, and divided by the number of cables.
In order to determine the tension in each cable required to support the cargo in static equilibrium, we can use Newton's Second Law of Motion.
This law states that the sum of the forces acting on an object must be equal to the object's mass multiplied by its acceleration.
The tension in each cable (T) must be equal to the weight of the cargo (W) divided by the number of cables (n).
So the equation would be:
T = W/n.
To find the value of T, we can use the formula
W = mg
where m is the mass of the cargo and g is the acceleration due to gravity.
Plugging this into the equation for T, we have:
T = mg/n.
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imagine you have a sensitive radio telescope and you would like to look at the sun. is it reasonable to expect that you would see it?
Yes, it is reasonable to expect that you would see the Sun with a sensitive radio telescope.
Radio waves can penetrate through the clouds and the atmosphere, so with a powerful radio telescope you can observe the Sun even on a cloudy day.
Gather the necessary components of the radio telescope, such as a dish and receiver. Point the radio telescope towards the Sun. Tune the receiver to the proper frequency. Take a look at the results from the telescope and observe the Sun.
Therefore, you can expect that you would see the Sun with a sensitive radio telescope.
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what approximate wind direction, speed, and temperature (relative to isa) should a pilot expect when planning for a flight over emi at fl 270?
The wind direction, speed, and temperature that a pilot should expect when planning for a flight over EMI at FL 270 are as follows:
Wind direction: 240 degrees True
Wind speed: 25 knots
Temperature: -10 degrees Celsius
EMI is a waypoint in the North Atlantic Track System, located in the middle of the ocean. When planning for a flight over this area, a pilot must take into account the wind and temperature conditions at that altitude (FL 270) to ensure the safety and efficiency of the flight.
These conditions can be obtained from weather forecasts and/or real-time data provided by the aircraft's instruments or other sources. The wind direction, speed, and temperature are all factors that affect the aircraft's performance, fuel consumption, and other operational parameters, and must be carefully considered in the flight planning process.
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what would the rotation period of the earth have to be for persons and objects at the equator to experience apparent weightlessness?
In order for people and objects at the equator to experience apparent weightlessness, the rotation period of the earth would have to be 84 minutes.
The centrifugal force caused by the rotation of the earth would have to be equal to the force of gravity in order for this to occur. This is because the centrifugal force would counteract the force of gravity and create the illusion of weightlessness.
To calculate the required rotation period, we can use the following formula:
rotation period = 2π√(r/g)where r is the radius of the earth and g is the acceleration due to gravity.
At the equator, the radius of the earth is approximately 6,378 km and the acceleration due to gravity is approximately 9.81 m/s^2.
Rotation period = 2π√(6,378,000/9.81)
rotation period ≈ 5066 seconds
rotation period ≈ 84 minutes
Therefore, the rotation period of the earth would have to be approximately 84 minutes for people and objects at the equator to experience apparent weightlessness.
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gunther is trying to push a 10 kg box. the coefficient of static friction between a 10 kg object and the floor is 0.50. what is the maximum force that can be applied on the object before it starts moving?
The maximum force that can be applied to the object before it starts moving is 49 N
To calculate the maximum force that can be applied to the object before it starts moving, we need to use the formula:
Fmax = μsN
where μs is the coefficient of static friction, N is the normal force exerted on the object, and F(max) is the maximum force that can be applied to the object before it starts moving.
Mass of the box = 10 kg and Coefficient of static friction between a 10 kg object and the floor = 0.50.
Normal force exerted on the box, N = mg (where g is the acceleration due to gravity = 9.8 m/s²)
So, N = 10 kg × 9.8 m/s² = 98N.
We can now use the above formula to calculate the maximum force that can be applied to the object before it starts moving:
Fmax = μsN = 0.50 × 98 N = 49 N.
Therefore, the maximum force that can be applied to the object before it starts moving, having a coefficient of static friction of 0.50 is 49 N.
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A student builds an electromagnet using a variable power source and 40 turns of wire. The electromagnet is used to pick up metal paper clips. The student changes the voltage and counts the number of paper clips that are picked up. Which table could be the data the student collected?
Table A
Table B
Table C
Table D
The table that could be the data the student collected is table D.
What is an electromagnet?An electromagnet is described as a type of magnet in which the magnetic field is produced by an electric current and usually consist of wire wound into a coil.
If student builds an electromagnet using a variable power source and 40 turns of wire. We have it that the student changes the voltage and counts the number of paper clips that are picked up. The table described below could perfectly described the scenario.
This is Table D
Voltage (V)
3
6
9
12
Number of paper clips
9
18
27
36
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A string is stretched to a length of 238 cm and both ends are fixed. If the density of the string is 0.014 g/cm, and its tension is 1610 N, what is the fundamental frequency? Answer in units of Hz.
Answer:
The fundamental frequency of a vibrating string is given by:
f = (1/2L) √(T/μ)
where L is the length of the string, T is the tension in the string, and μ is the linear density (mass per unit length) of the string.
In this problem, L = 238 cm, T = 1610 N, and μ = 0.014 g/cm = 0.00014 kg/cm. We can convert the units of length and mass to SI units (m and kg) to get the frequency in Hz:
L = 2.38 m
μ = 0.00014 kg/m
Substituting these values into the formula, we get:
f = (1/2L) √(T/μ)
f = (1/2 × 2.38 m) √(1610 N / 0.00014 kg/m)
f = 106.8 Hz
Therefore, the fundamental frequency of the string is 106.8 Hz.
Answer:
The fundamental frequency of the string is 225.29 Hz.
Explanation:
To calculate the fundamental frequency of the string, we use the formula below.
Formula:
F' = (1/2l)√(T/m)............... Equation 1
Where:
F' = Fundamental frequency of the string
l = length of the string
T = Tension on the string
m = mass per unit length of the string
From the question,
Given:
l = 238 cm = 2.38 m
T = 1610 N
m = 0.014 g/cm = 0.0014 kg/m
Substitute these values into equation 1
F' = 1/(2×2.38)[√(1610/0.0014)]
F' = (0.210){√(1150000)
F' = (0.210×1072.38)
F' = 225.29 Hz.
Hence, the fundamental frequency of the string is 225.29 Hz.
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you are sitting in a closed room with no windows. the only light in the room originates from two identical bare, incandescent light bulbs. one is located on the wall to your left; and the other is located on the wall to your right. bored, you look up at the ceiling and realize there is no interference pattern. why is there no interference pattern?
No stable interference pattern is formed on the ceiling.
Instead, you would see a simple combination of the light emitted by both bulbs, creating a uniformly lit ceiling.
The absence of an interference pattern in the scenario you described is due to the nature of the light sources and the way they emit light.
Incandescent light bulbs emit incoherent light, which means the light waves from these bulbs are not in phase with each other.
An interference pattern is created when two coherent light sources, like lasers, emit light waves that are in phase with each other.
When these light waves meet, they create a pattern of constructive and destructive interference.
Constructive interference occurs when the crests (or high points) of two light waves align, resulting in a brighter area, while destructive interference occurs when the crest of one wave aligns with the trough (or low point) of another wave, resulting in a darker area.
This alternating pattern of bright and dark areas is known as an interference pattern.
However, in your scenario with two incandescent light bulbs, the light waves emitted by each bulb are incoherent, meaning they have random phases and do not align consistently.
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suppose a 63-kg gymnast climbs a rope. what is the tension in the rope in newtons if he accelerates upward at a rate of 2.5 m/s2?
The tension in the rope is 173.55 N.
Using Newton's second law of motion, we know that the force (F) exerted on an object is equal to its mass (m) times its acceleration (a): F = ma. In this case, the gymnast's weight is acting downward, so the tension in the rope must be greater than the weight to provide the necessary upward force to accelerate the gymnast upward.
Thus, we can calculate the tension in the rope as follows:
Tension - Weight = ma
T - mg = ma
where T is the tension in the rope, m is the mass of the gymnast, g is the acceleration due to gravity (9.8 m/s^2), and a is the acceleration of the gymnast upward.
T - (63 kg)(9.8 m/s^2) = (63 kg)(2.5 m/s^2)
T = (63 kg)(9.8 m/s^2 + 2.5 m/s^2) = 173.55 N
Therefore, the tension in the rope is 173.55 N, which is the force required to lift the gymnast upward with an acceleration of 2.5 m/s^2.
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additional required problem: two people, one of mass 85 kg and the other of mass 55 kg, sit in a rowboat of mass 78 kg. with the boat initially at rest, the two people, who have been sitting at opposite ends of the boat, 3.0 m apart from each other, now exchange seats. how far and in what direction will the boat move?
The boat will not move since the two people exchanging seats will not cause a net linear momentum on the boat.
The equation for linear momentum is P = mv, where m is the mass and v is the velocity of an object.
Since the boat is initially at rest, its linear momentum is P = 0.
Let's start by calculating the linear momentum before the exchange:
P = (85kg)(0) + (55kg)(0) = 0
After the people exchange seats, the linear momentum of the boat is no longer 0.
Now let's calculate the linear momentum after the exchange:
P = (85kg)(v) + (55kg)(-v) = (140kg)v
Since the total linear momentum is conserved, we can equate the two linear momentums and solve for v:
0 = (140kg)v
v = 0
The equation for linear momentum is P = mv, where m is the mass and v is the velocity of an object.
Therefore, the boat will not move since the velocity of the boat is 0.
This makes sense since the two people exchanging seats will not cause a net linear momentum on the boat.
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a different guitar string makes 7680 oscillations in 30 seconds. what is the frequency of the sound waves that it creates?
The frequency of the sound waves created by the guitar string is 256 Hz.
The number of oscillations of the guitar string in 30 seconds is 7680.
The frequency of the guitar string is defined as the number of oscillations per second, so we can calculate the frequency by dividing the total number of oscillations by the time it took to make them:
frequency = number of oscillations / time
frequency = 7680 / 30 seconds = 256 Hz
Therefore, the frequency of the sound waves created by the guitar string is 256 Hz.
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a scuba diver and her gear displace a volume of 69.6 l and have a total mass of 72.8 kg. a) what is the buoyant force on the diver in seawater?
The Buoyant force on a scuba diver if, scuba diver and her gear displace a volume of 69.6 and have a total mass of 72.8 kg is 70.86 N.
The Archimedes' principle states that states that the buoyant force is equal to the weight of the fluid displaced by the object.
So, the buoyant force on the diver can be calculated as follows:
Buoyant force = Weight of fluid displaced
It can also be written as
Buoyant force = Density of fluid × Volume of fluid displaced × gravitational acceleration
In seawater, the density is typically about 1025 kg/m³.
First, convert the volume from liters to cubic meters.1 liter = 0.001 m³
69.6 liters = 69.6 × 0.001 = 0.0696 m³
So, the volume of seawater displaced by the diver is 0.0696 m³.
Now, we can calculate the buoyant force.
Buoyant force = 1025 kg/m³ × 0.0696 m³ × 9.81 m/s²
Buoyant force = 70.86 N
Therefore, the buoyant force on the diver in seawater is 70.86 N.
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a bullet of mass 0.010 kg and speed of 100 m/s is brought to rest in a wooden block after penetrating a distance of 0.10 m. this process takes 0.02 second. the magnitude of the impulse delivered to the bullet by the block during this time is
The magnitude of the impulse delivered to the bullet by the block during this time is 0.90 Ns.
The mass of the bullet is given as 0.010 kg and its initial speed as 100 m/s. After travelling 0.10 m, the bullet comes to rest in a wooden block. The time taken for the bullet to stop is 0.02 seconds. We need to calculate the magnitude of the impulse delivered to the bullet by the block during this time. We can use the formula for impulse, which is Impulse = Force × Time. Impulse is defined as the change in momentum. Thus, we can use the equation m₁v₁ - m₁v₂ = F×t , where m₁ is the mass of the bullet, v₁ is the initial speed of the bullet, v₂ is the final velocity of the bullet, t is the time for which the force acts, and F is the force applied on the bullet. In this case, we know the mass and initial speed of the bullet. We need to find the final velocity of the bullet to calculate the force. We can use the formula for final velocity, which is v₂ = u + at , where u is the initial velocity of the bullet, a is the acceleration due to the force acting on the bullet, and t is the time for which the force acts. Here, the force acting on the bullet is the force of the wooden block, and the acceleration is given by a = F/m₁ . Thus, we have v₂ = u + F/m₁ × t . The distance travelled by the bullet is given as 0.10 m. We can use the formula for distance travelled, which is s = ut + ½at² . Here, s is the distance travelled by the bullet, u is the initial velocity of the bullet, a is the acceleration due to the force acting on the bullet, and t is the time for which the force acts. We have u = 100 m/s, s = 0.10 m, and t = 0.02 s. We can use this equation to calculate the acceleration of the bullet. Solving for a, we get a = (2s - ut) / t² = (2 × 0.10 - 100 × 0.02) / (0.02)² = -450 m/s². Here, the negative sign indicates that the acceleration is in the opposite direction to the velocity of the bullet. Substituting this value of a in the equation for v₂, we get v₂ = 100 - 450 × 0.02 / 0.010 = 10 m/s. Thus, the change in velocity of the bullet is Δv = v₂ - v₁ = 10 - 100 = -90 m/s. The magnitude of the impulse delivered to the bullet by the block during this time is |Impulse| = m₁ × |Δv| = 0.010 × 90 = 0.90 Ns. Therefore, the magnitude of the impulse delivered to the bullet by the block during this time is 0.90 Ns.
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which of the following is not connected or involved with shock metamorphism? group of answer choices asteroids coesite pegmatites impactiles
Shock metamorphism is a type of metamorphism caused by an impact, such as from a meteorite or an asteroid. So the answer to this question is asteroids.
Shock metamorphism refers to the changes that occur in rocks when they are subjected to high-pressure shock waves caused by impacts from asteroids, comets, or meteorites. The impact creates high temperatures and pressures that cause the mineral composition of the rock to be changed. Coesite and impactites are two common rocks found with shock metamorphism, while pegmatites are not related to shock metamorphism. Impactiles are objects that impact and cause shock metamorphism in rocks. Asteroids and comets are examples of impacts that can cause shock metamorphism. Pegmatites, on the other hand, are coarse-grained igneous rocks that form from the slow cooling of magma.
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find the force between charges of +10.0 x 10*C and -50.0 x 10*C located 20>0cm apart
20 cm apart, the charges of +1.0 x 10⁻⁶ C and –1.0 x 10⁻⁶ C exert a force of 449.5 N on one another. This force is directed from the negative charge to the positive charge.
How can the force between two charges be determined?According to Coulomb's law, the force F between two point charges, q1 and q2, that are separated by a distance r, is computed as F=k|q1q2|r2.
It is possible to determine the force between two point charges using Coulomb's law:
F = k*(q1*q2)/r²
In this case, we have[tex]q1 = +10.0 x 10^-6 C, q2 = -50.0 x 10^-6 C, and r = 20 cm = 0.2 m.[/tex]
Plugging in these values, we get:
[tex]F = (8.99 x 10^9 N m^2/C^2) * [(+10.0 x 10^-6 C) * (-50.0 x 10^-6 C)] / (0.2 m)^2[/tex]
Simplifying, we get:
F = -449.5 N.
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which term defines the distance from rest to crest, or from rest to trough?responsesamplitudeamplitudefrequencyfrequencyperiodperiodspeed
Amplitude is not measured from peak to trough, but from rest to peak or rest to trough.
The highest and lowest points on the surface of a wave are called crests and troughs respectively. The vertical distance between the peak and the trough is the height of the waves. The horizontal distance between two successive peaks or troughs is called the wavelength.
The amplitude of a wave is the maximum displacement of a particle on a medium with respect to its position of rest.
The amplitude can be thought of as the distance between rest and the peak. The amplitude from the rest position to the dip position can be measured in a similar manner.
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A billiard ball of mass m = 0.150 kg hits the cushion of a billiard table at an angle of θ1 = 60.0 degrees at a speed of v1 = 2.50 m/s. It bounces off at an angle of θ2 = 47.0 degrees and a speed of v2 = 2.20 m/s.
a) What is the magnitude of the change in the momentum of the billiard ball?
b) In which direction does the change of momentum vector point? (Take the x-axis along the cushion and specify your answer in degrees.)
The magnitude of the change in the momentum of the billiard ball is 0.268 kg⋅m/s. The direction of the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.
This result can be found by using the equation for conservation of momentum, which states that both the magnitude and the direction of the momentum before and after the collision must be the same.
Since the mass and the speed of the ball changed, the direction of the vector must have changed as well. In this case, the vector changed direction from 60 degrees to 47 degrees, a difference of 13 degrees.
This means that the vector must have rotated counterclockwise by 13 degrees, or in other words, the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.
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photo effect: the photo emitting electrode in a photo effect experiment has a work function of 3.56 ev. what is the longest wavelength the light can have for a photo current to occur? state the wavelength in nm units
The longest wavelength of the light required to cause photoelectric effect is 349 nm (in nm units).
A photoelectric effect occurs when light falls on a metal surface, causing electrons to be emitted from the metal surface. It's a phenomenon that demonstrates the particle-like nature of light, which is made up of photons, as well as the wave-like nature of light.
Einstein first proposed the idea of the photoelectric effect, which eventually helped him win the Nobel Prize in Physics in 1921.Photoelectric Effect’s Formula
The photoelectric effect's formula is as follows:
Kinetic Energy = Energy of Photon - Work Function
KE = hf - Φ
For this question, we have work function, and we will use it to find the longest wavelength.
The formula of work function is given as Φ= hf0
Where f0 is the threshold frequency (frequency of the incoming light, below which the photoelectric effect does not occur).h = Planck’s constant = 6.626 x 10^-34 J s = 4.136 x 10^-15 eV s
The longest wavelength of the light required to cause photoelectric effect is given asλ = c / f
Here, λ is the wavelength of the incoming light, c is the speed of light, and f is the frequency of the incoming light.
We have to solve the work function equation to find the threshold frequency.
The formula is given asf0 = Φ/h
Substituting the values, we get:f0 = 3.56 eV / 4.136 x 10^-15 eV s = 8.60 x 10^14 Hz
To find the longest wavelength, we use the following formula:
λmax = c / f0 = (3 x 10^8 m/s) / (8.60 x 10^14 Hz) = 3.49 x 10^-7 m = 349 nm
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lo4 pos what advantages does the hubble space telescope (hst) have over ground-based telescopes? list some disadvantages
The Hubble Space Telescope offers clear and stable views of the cosmos without atmospheric distortion but has disadvantages including aging infrastructure, limited sensitivity to certain wavelengths, and difficulty with maintenance.
Advantages of Hubble Space Telescope:
Clearer and more stable view of the cosmos, and its sensitivity to a wider range of light. Not affected by atmospheric distortions.It can see far more clearly than a ground-based telescope.The following are the disadvantages of the Hubble Space Telescope:
Aging infrastructure, which has resulted in frequent maintenance and repairs. Its sensitivity to UV and IR radiation was also limited by its design. Not as easy to maintain as ground-based telescopes. The HST's images are often subject to light pollution, which can make it difficult to see faint objects.While the Hubble Space Telescope has revolutionized astronomy and made many groundbreaking discoveries, it also faces challenges and limitations that must be addressed as new space-based observatories are developed to continue advancing our understanding of the universe.
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a 1-kg rock that weighs 10 n is thrown straight upward at 20 m/s. neglecting air resistance, the net force that acts on it when it is half way to the top of its path is
A net force of 10 N acts on the rock when it is halfway to the top of its path.
The net force acting on the rock can be calculated using the following equation:
Fnet = ma
Where Fnet is the net force, m is the mass, and a is the acceleration.
When the rock is halfway to the top of its path, its velocity is zero since it momentarily stops at the top of its motion. As a result, its acceleration is equal to the acceleration due to gravity, which is -10 m/s² since it is acting in the opposite direction to the upward direction. This is the gravitational force acting on the rock.
We can now calculate the net force acting on the rock at this point in its motion:
Fnet = ma
Fnet = (1 kg)(-10 m/s²)
Fnet = -10 N
Since the acceleration due to gravity is acting downward and the rock is moving upward, the net force is equal to the force of gravity, which is 10 N.
Therefore, the net force that acts on the rock when it is halfway to the top of its path is -10 N or 10 N in the downward direction. This net force is equal in magnitude to the weight of the rock.
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if a bag has a mass of 25 kg, how much force must you apply vertically to lift it off of a baggage cart?
A force of 245 N must be applied vertically to lift the bag off the baggage cart.
The force that must be applied vertically to lift a bag off a baggage cart, given that the bag has a mass of 25 kg, can be determined using the formula F = m*g
where F is force, m is mass, and g is acceleration due to gravity. The value of g is 9.8 m/s².So, F = 25 kg x 9.8 m/s² = 245 N. Therefore, a force of 245 N must be applied vertically to lift the bag off the baggage cart.
The mass of the bag = 25 kg.The formula used is, F = m*gwhereF = Force required to lift the bagm = Mass of the bagg = Acceleration due to gravityF = 25 kg x 9.8 m/s² = 245 N.
Therefore, a force of 245 N must be applied vertically to lift the bag off the baggage cart.
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What Enlightenment idea is represented by the headline
The headline "Enlightenment ideas of freedom, equality, and justice for all" represents the idea of the Enlightenment that human beings are rational, capable of determining right from wrong, and deserving of rights and freedoms, such as freedom of speech, freedom of religion, and equality before the law.
These ideas were a major factor in the shift away from absolute monarchies, and towards governments of the people, by the people, and for the people. The Enlightenment period also saw the development of democracy and of the rule of law, where the government is subject to a set of laws, rather than relying on the whims of the ruler. Enlightenment thinkers sought to empower the individual, giving people the freedom to think and act as they pleased, rather than relying on the decisions of rulers.
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while the general equations for the first and second law are written in terms of how the universe changes, dr. laude's preference is that we quickly rewrite them to reflect changes in what?
This is due to the fact that the first and second laws of thermodynamics are universally applicable fundamental principles that can be utilised to examine particular systems and processes.
How do chemical processes relate to the first and second laws of thermodynamics?The part of thermodynamics that deals with chemical reactions is called chemical thermodynamics. The first law states that energy is conserved and cannot be created or destroyed. Second law: When natural processes in a closed system result in a rise in entropy, they are spontaneous.
The second law of thermodynamics is what?According to the second rule of thermodynamics, an isolated system that is out of equilibrium over time must increase in entropy until it reaches the ultimate equilibrium value.
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how does matter affect your daily lives?
Matter affects our daily lives in the sense all is composed of matter and energy.
What are matter and energy in the Universe and daily life?Matter and energy in the Universe and daily life are two basic elements that characterize the physic system and allow us to understand the world. In regard to matter, it is something that occupies space and has mass, while energy can perform work.
Therefore, with this data, we can see that matter and energy in the Universe and daily life are fundamental to understanding the universe.
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what is the impulse experienced by a 65.8 kg halfback encountering a force of 1025 n for 0.350 seconds?
The 65.8 kg halfback experienced an impulse of 359 Ns when subjected to a force of 1025 N for a duration of 0.350 seconds.
The formula for impulse is given below:
Impulse = force × time
Where F is the force applied on the object.
t is the time for which the force is applied.
"I" is the impulse experienced by the object.
Substituting the given values,
Force (F) = 1025 N Time (t ) = 0.350 s Impulse I = ?
Impulse = force × time
I = F × t
I = 1025 × 0.350
I = 358.75 Ns or 359 Ns
The impulse experienced by a 65.8 kg halfback encountering a force of 1025 N for 0.350 seconds is 359 Ns.
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